If the ordinary hazard density is 0.15 gpm/ft² and the area of coverage is 400 sq ft, what is the minimum flow required?

To determine the minimum flow required for an ordinary hazard scenario, you multiply the ordinary hazard density by the area of coverage. Here, the ordinary hazard density is given as 0.15 gallons per minute per square foot (gpm/ft²), and the area of coverage is 400 square feet.

The calculation would be:

Minimum flow required = Hazard density × Area of coverage

Substituting the values into the formula:

Minimum flow required = 0.15 gpm/ft² × 400 ft² = 60 gpm

This means that for an area of 400 square feet under an ordinary hazard condition, a minimum flow of 60 gallons per minute is necessary to ensure adequate fire protection. The other options do not meet this requirement, making 60 gpm the correct answer.